70 lines
2.1 KiB
Python
70 lines
2.1 KiB
Python
import os
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import yaml
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import openpyxl
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from grade_assignments import ASSIGNMENT_DIR, find_assignment_yml, EXCEL_PATH
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def check_all_ymls():
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"""检查Excel中记录的YML文件是否存在且有效"""
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print(f"正在检查Excel: {EXCEL_PATH}")
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# 读取Excel获取学生名单
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try:
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wb = openpyxl.load_workbook(EXCEL_PATH)
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ws = wb.active
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# 获取标题行确定列索引
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headers = [cell.value for cell in ws[1]]
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name_col = headers.index('填写人')
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students = []
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for row in ws.iter_rows(min_row=2, values_only=True):
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if len(row) > name_col and row[name_col]: # 确保有足够列且姓名不为空
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students.append(row[name_col])
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print(f"找到 {len(students)} 条学生记录")
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except Exception as e:
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print(f"读取Excel失败: {str(e)}")
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return False
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# 检查每个学生的YML文件
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missing_files = []
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invalid_files = []
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valid_count = 0
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for student in students:
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yml_path = find_assignment_yml(student)
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if not yml_path:
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missing_files.append(student)
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continue
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try:
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with open(yml_path, 'r', encoding='utf-8') as f:
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yaml.safe_load(f)
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valid_count += 1
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print(f"[✓] {os.path.basename(yml_path)} - 有效")
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except Exception as e:
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invalid_files.append(student)
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print(f"[×] {os.path.basename(yml_path)} - 无效: {str(e)}")
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# 输出汇总报告
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print("\n检查完成:")
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print(f"- 有效文件: {valid_count}/{len(students)}")
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if missing_files:
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print("\n以下学生缺少YML文件:")
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for name in missing_files:
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print(f" - {name}")
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if invalid_files:
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print("\n以下学生的YML文件无效:")
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for name in invalid_files:
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print(f" - {name}")
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return not (missing_files or invalid_files)
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if __name__ == "__main__":
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if check_all_ymls():
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print("\n所有YML文件检查通过")
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else:
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print("\n发现无效YML文件，请修复后再运行")
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